Why the value square of Log2 not same when calculated manually? [on hold]

Good day,

I have a problem according to Log2[] towards to matrix element.

mu = Log2[{{2, Cos[Pi]}, {4, 3}}], 

The output mu I get are :

{{1, (I*Pi)/Log[2]}, {2, Log[3]/Log[2]}}. 

When I square the mu as below,

 squaremu = (Log2[{{2, Cos[Pi]}, {4, 3}}])^2, 

I get the output of squaremu;

{{1, -(Pi^2/Log[2]^2)}, {4, Log[3]^2/Log[2]^2}} 

Then I convert output to number by putting //N as below;

N[{{1, -(Pi^2/Log[2]^2)}, {4, Log[3]^2/Log[2]^2}}] 

I get the final result as

{{1., -20.5423}, {4., 2.51211}} 

My problem:

1.what is exactly the value of Pi here? As I know, the value is 3.142. The result of -20.5423 is not same as I calculate manually=108.9414.

2.Why when we do the Log2 towards (-1) it become

I*Pi 

where the Pi come from?

Please help me.Thank you

Replay

Category: functions Time: 2016-07-31 Views: 4

Related post

iOS development

Android development

Python development

JAVA development

Development language

PHP development

Ruby development

search

Front-end development

Database

development tools

Open Platform

Javascript development

.NET development

cloud computing

server

Copyright (C) avrocks.com, All Rights Reserved.

processed in 0.163 (s). 12 q(s)